Question

In an A.P. the sum of three consecutive terms is 30 and their products is

360. Find the terms. (Assume that three consecutive terms in an A.P. are

a-d, a, a+d)​

Answer 1

Answer:

a-d+a+a-d=30

3a=30

a=10

substituting the value of a=10 in a-d*a*a-d

10-d*10+d=360/10

100-d2=36

-D2=36-100

-d2= -64

d2=64

therefore

d=8

therefore the ap is

10,18,26,34....

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