In an A.P. the sum of three consecutive terms is 30 and their products is
360. Find the terms. (Assume that three consecutive terms in an A.P. are
a-d, a, a+d)
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Answer:
a-d+a+a-d=30
3a=30
a=10
substituting the value of a=10 in a-d*a*a-d
10-d*10+d=360/10
100-d2=36
-D2=36-100
-d2= -64
d2=64
therefore
d=8
therefore the ap is
10,18,26,34....
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