In an ∆ABC, if 2A=3B=6C, find each angle of ∆ABC
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Answered by
4
3/2B+B+1/2B=180
angle A=90 B=60 and C=30
angle A=90 B=60 and C=30
Answered by
4
1/2x+1/3x+1/6x = 180
So x = 180
1/2*180=90
1/3*180=60
1/6*180=30
So x = 180
1/2*180=90
1/3*180=60
1/6*180=30
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