In an AC circuit , the voltage applied is E = E₀sinωt . The resultant current in the circuit is I = I₀sin(ωt-π/2) . The power consuption in the circuit is given by [AIEEE 2007]
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Answered by
0
Answer:
0
Explanation:
Average Power Consumed. P
Average
=VIcosϕ where ϕ is the phase angle between the current and the voltage and where V and I are understood to be the effective or rms values of the voltage and current. The term cosϕ is called the "power factor" for the circuit.
As in our case the phase difference is
π/2 & as cos (π/2) = 0
So power consumed is 0.
Answered by
4
Answer:
The power consumption in the curcuit is 0
Explanation:
For given circuit, current is lagging the voltage by π/2 ,
- ∵P = VIcosθ
- But, θ = π/2
- ∴ P= VIcos(π/2) =0
We know, Cosπ/2 = 0
so circuit is purely inductive and there is no power consumption in the circuit . The work done by battery is stored as magnetic energy in the inductor.
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