In an acoustics class, 120 students are male and 100 students are female. 25% of the male students and 20% of the female students are engineering students.
20% of the male engineering students and 25% of the female engineering students passed the final exam.
What percentage of engineering students passed the exam?
Answers
Step-by-step explanation:
No.of female students = 100
Among them 20% are engineering students
= [20/100]×100 = 20
So, the female engineering student = 20
Among these 25% female engineering students passed the final exam
= [20×25]×100 = 5
So no.of female students passed exam = 5
No.of male students = 120
Among these 25% are engineering students
= [25×120]/100 = 30
from these 20% of students are passed
= [20×30]/100 = 6
Hence total no.of students who passed exam = female + male
= 5+6 = 11 Students
Total number of engineering students in class
= 20 + 30 = 50 students
Percentage of students passed exam is
= [11/50]×100
= 22%
«Thank you «
Answer:
the male engineering students= 120*25/100
=30
the female engineering students=100*20/100
=20
the passed male engineering students=30*20/100
=6
the passed female engineering students=20*25/100
=5
the pecentage of passed engineering students is={(6+5)/50*100}%
={11/50*100}%
=(11*2)%
=22%
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