In an acute angled triangle abc, s is any point on bc.Prove that ab+bc+ca>2as
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Given -----> ABC is a triangle and S is any point on BC.
To prove------>AB+BC+CA > 2AS
Proof---->
In triangle ABS,
AB+ BS > AS ~~~~~(1)
In triangle ASC,
AS + SC >AS ~~~~~(2)
( Since, the sum of two sides of a triangle is greater than the third side.)
Adding (1) and (2) , we get :-
AB + (BS + AS) + SC > AS + AS
AB + BC + CA > 2 AS proved_.
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To prove------>AB+BC+CA > 2AS
Proof---->
In triangle ABS,
AB+ BS > AS ~~~~~(1)
In triangle ASC,
AS + SC >AS ~~~~~(2)
( Since, the sum of two sides of a triangle is greater than the third side.)
Adding (1) and (2) , we get :-
AB + (BS + AS) + SC > AS + AS
AB + BC + CA > 2 AS proved_.
Hope it will help you.
If you like , then follow me and mark as brainliest.
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