Question

In an ammeter 0.2% of main current passes through
the galvanometer. If resistance of galvanometer is
G, then resistance of ammeter will be :-


(1) 1/499G (2) 499/500 G (3)1/ 500 G (4) 500/499​

Answer 1

The resistance of ammeter will be 1/499 G.

Explanation:

For ammeter:

0.0002 l x G = 0.9981 x rg

rg = 0.002 / 0.998 G

That is

rg = 0.002004

    = 1/499 G

Hence the resistance of ammeter will be 1/499 G.

Also learn more

A wire of radius 0.4 to mm and resistivity 44 into 10 power minus 8 ohm metre is available in a laboratory calculate the length of a wire needed to have a resistance of 15 ohm ?

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Answer 2

Answer:

1/500

Explanation:

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