Question

In an ammeter, 10 % of main current is passing through the galvanometer. If the resistance of the galvanometer is g, then the shunt resistance, in ohm is

Answer 1

Answer:

g/9

Explanation:

Given  :    Ig=0.1I              Rg=G

Shunt resistance   Rs: (1grg)/I-Ig) = (0.1I)G/I-0.1I

= G/9

Answer 2

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