Question

In an ap 12th term is - 13 and the sum of of first 4 terms is 24find the sum of drst 10 terms

Answer 1

Answer

AnswerGiven that :-

AnswerGiven that :-12th term of the A.P is −13

AnswerGiven that :-12th term of the A.P is −13sum of first four terms is 24

four terms is 24Let, the 1st term of the A.P is a.

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)d

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12⇒a=212−3d------(ii)

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12⇒a=212−3d------(ii)comparing (i) and (ii) we get,

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12⇒a=212−3d------(ii)comparing (i) and (ii) we get,−13−11d=212−3d 

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12⇒a=212−3d------(ii)comparing (i) and (ii) we get,−13−11d=212−3d     

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12⇒a=212−3d------(ii)comparing (i) and (ii) we get,−13−11d=212−3d     ⇒−22d+3d=26+12   

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12⇒a=212−3d------(ii)comparing (i) and (ii) we get,−13−11d=212−3d     ⇒−22d+3d=26+12   ⇒−19d=38          ⇒d=−2

four terms is 24Let, the 1st term of the A.P is a.and common difference of the A.P is d.We know, the formula for nth of an A.P. is ,tn=a+(n−1)dand, the formula for the sum of n−termsof an A.P. is,Sn=2n[2a+(n−1)d]By the question,t12⇒a+(12−1)d=−13⇒a+11d=−13⇒a=−13−11d------(i)S4→24[2a+(4−1)d]=24⇒2a+3d=12⇒a=212−3d------(ii)comparing (i) and (ii) we get,−13−11d=212−3d     ⇒−22d+3d=26+12   ⇒−19d=38          ⇒d=−2Now, from (i) we get, 

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