Question

in an AP 15th term is 75 and 4th term is 20 then it's common difference is a.55. b. 11. c.5 d.3.​

Answer 1

Answer:

hope this example helps you

Answer 2

Theory :-

For an arithmetic progression, if

a = First term of the A.P

d = Common difference of the A.P

Then,

Tₙ = (a + (n - 1)d) where Tₙ = nth term of the A.P

Solution :-

For the given A.P

T₁₅ = T₁ + (15 - 1)d = 75

T₄ = T₁ + (4 - 1)d = 20

Where

T₁ = First term of the A.P

d = Common difference of the A.P

T₁₅ = 15th term of the A.P

T₄ = 4th term of the A.P

So,

On subtracting (2) - (1)

We get,

11d = 55

or, d = 5

Hence, common difference of the given A.P is 5.

Hope u liked my answer

Pls mark me as brainliest

Thanks.