Question

In an AP 4+12+36+............find s3:s6

Answer 1

Answer:

S3 = 3/2[2a+(n-1)d]

S6. 6/2[2a+(n-1)d]

= 3/2[2(4)+(3-1)(8)]

3[2(4)+(6-1)(8)]

= 3/2[8+2(8)]

3[8+5(8)]

= 3/2[8+16]

3[8+40]

= 3/2(24)

3(48)

= 3(12)

144

= 36

144

= 6×6.

6×6×4

= 1

4

= 1 : 4

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Answer 2

Answer:

a=4 d=12-4=8

Sn=n/2(2a+(n-1)*d) Sn=n/2(2a+(n-1)*d)

S3=3/2(2*4)+(3-1)(8) s6=6/2(2*4+(6-1)*8)

=3/2(8+2*8 =6/2(8+5*8)

=3/2(8+16) =6/2(8+40)

=3/2(24) =6/2(48)

=3*12 =6*24

S3 =36 S6 =144

When

S3:S6=6*6/6*6*4=1/4=1:4 answer..

Step-by-step explanation:

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