In an AP 5 times the 5th term is equal to 8 times the 8th term, then its 13 th term is:
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5(a5)=8(a8)
5(a+4d)=8(a+7d)
5a+20d=8a+56d
3a=36d
a=12d
a13=a+12d
a13=12d+12d
a13=24d...
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