Question

In an AP an= 3+5n. Find the AP​

Answer 1

In an AP

In an AP t2-t1=t3-t2

In an AP t2-t1=t3-t2Given

In an AP t2-t1=t3-t2Givenan=3+5n

In an AP t2-t1=t3-t2Givenan=3+5nput n=1

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=2

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2n=3

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2n=33+5*3=18=t3

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2n=33+5*3=18=t3t1-t2=8-13=-5

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2n=33+5*3=18=t3t1-t2=8-13=-5t3-t2=13-18=-5

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2n=33+5*3=18=t3t1-t2=8-13=-5t3-t2=13-18=-5therefore t1-t2=t3-t2

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2n=33+5*3=18=t3t1-t2=8-13=-5t3-t2=13-18=-5therefore t1-t2=t3-t2 -5=-5

In an AP t2-t1=t3-t2Givenan=3+5nput n=13+5*1=8=a=t1put n=23+5*2=13=t2n=33+5*3=18=t3t1-t2=8-13=-5t3-t2=13-18=-5therefore t1-t2=t3-t2 -5=-5 it is an AP

HOPE IT HELPS

Answer 2

an=3+5n

so,

x1=3+5×1

=8

x2=3+5×2

= 3+10

= 13

cd= x2-x1

= 13-8

=5

so the AP is,

8,13,18,23,28,.........

hope this helps u....