In an Ap given a=5, d=3,an=50, find n and sn
Answers
Answered by
156
an=50
a+(n-1)d=50
5+(n-1)3=50
3n-3=50-5
3n=50+3-5
3n=48
n=48/3
n=16
sn=n/2 (2a+n
a+(n-1)d=50
5+(n-1)3=50
3n-3=50-5
3n=50+3-5
3n=48
n=48/3
n=16
sn=n/2 (2a+n
12345rhythm:
sn=n/2 (2a+(n-1)d) = 8 (2×5+(8-1)3 =8 (10+21) =8×31 =248
Answered by
91
Answer:
Step-by-step explanation:
a=5, d=3, an=50, n=?, Sn=?
= a+(n-1)×d=50
=5+(n-1)×3=50
=5+3n-3=50
=3n=48
=n = 48/3
= n = 16
Now, let's find Sn=?
Sn= n/2
Sn=16/2[2a+(16-1)d]
=8[2×5+15×3]
=440
Hence, n=16 and S16 or Sn=440
Hope you guys understood and clear!!
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