If the length of a rectangular field is 7/2 of its breadth and its perimeter is 99 m, find the length and breadth of the field.
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Answered by
1
Let breadth be x,
So,length = 7x/2
Given that perimeter = 99
2(length + breadth) = 99
2(x + 7x/2) = 99
2x + 7x = 99
9x = 99
x = 11
Hence, breadth = x = 11 m
Length = 7(11)/2 = 77/2 = 38.5 m
So,length = 7x/2
Given that perimeter = 99
2(length + breadth) = 99
2(x + 7x/2) = 99
2x + 7x = 99
9x = 99
x = 11
Hence, breadth = x = 11 m
Length = 7(11)/2 = 77/2 = 38.5 m
Answered by
1
the length is 77m and breadth is 22m
as, if we take the breadthas x so
length=7/2 x
7/2x +x = 99m
9/2 x = 99m
9x = 198m
x = 198/9
x=22
hence, 22 X 7/2 = 77m = lenght
and breadth = 22m
as, if we take the breadthas x so
length=7/2 x
7/2x +x = 99m
9/2 x = 99m
9x = 198m
x = 198/9
x=22
hence, 22 X 7/2 = 77m = lenght
and breadth = 22m
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