In an AP if 12th term is -13 and the sum of the first four terms is 24 find the sum of the first 10 terms
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a12=a+11d
⇒-13=a+11d
s4=4/2(2a+3d)
⇒12=2a+3d
from above 2 equations d=-2 and a=9
∴s10=0
⇒-13=a+11d
s4=4/2(2a+3d)
⇒12=2a+3d
from above 2 equations d=-2 and a=9
∴s10=0
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