in an AP if 9th term is 449 and 449th term is 9 then find the common difference
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Here, a9 = 449 A449 = 9 Let a is the first term and d is the common difference of the AP Given 9th term of AP = 499 a + 8d = 499 Again 499th term of AP = 9 a + 498d = 9 Now subtract equation 1 and 2, we get a + 8d – (a + 498d) = 499 – 9 a + 8d – a – 498d = 499 – 9 –490d = 490 d = –490/490 d = –1
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