Question

In an AP, if a = 1 , nth term is 37 and d=2, then n is *


​

Answer 1

Answer:

n= 73

Step-by-step explanation:

tn= a +(n-1) d

t37=1+(37-1) 2

    n  = 1+36 x 2

     n  =1+ 72

    n  =73

Answer 2

GIVEN :–

• First term of A.P. (a) = 1

• Common difference (d) = 2

• nth term = 37

TO FIND :–

• Value of 'n' = ?

SOLUTION :–

• We know that nth term of A.P. is –

ㅤㅤㅤㅤㅤㅤㅤ

$\large \bf \dag\:\:{ \boxed{ \bf T_{n} = a + (n - 1)d}}$

ㅤ

• Now put the values –

ㅤ

$\implies \bf 37 = 1 + (n - 1)(2)$

ㅤ

$\implies \bf 37 - 1 = (n - 1)(2)$

ㅤ

$\implies \bf 36= (n - 1)(2)$

ㅤ

$\implies \bf (n - 1) = \cancel \dfrac{36}{2}$

ㅤ

$\implies \bf (n - 1) = 18$

ㅤ

$\implies \bf n = 18 + 1$

ㅤ

$\implies \large{ \boxed{ \bf n = 19}}$

ㅤ

▪︎Hence , 19th term is 37.