Question

In an AP : if a = 10, a₁₀ = 30, then d = ...........

9/20

20/17

20/9

50/9

11. 15th term from the last term of the AP : 10, 7, 4, ....., -62 is -

-38

-20

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Answer 1

Answer ⤵️

10) Here, common difference d = 5

Now,a↓10 - a↓7 = a+9d - a - 6d

= 3d = 3 × 5 = 15

option D is correct...

11)

here in this ap series

a=first term =10

d=commondiff.= -3

n=no. Of term =20

so, Tn= nth term = ?

so,

using formula.…

Tn=a+(n-1)d

=10+(20-1)(-3)

=10+19(-3)

= 10 -57= -47

so the required 20th term of given AP is -47,

i hope this is helpful to you.…………