in an ap if a =20 d= 40 n=10 find sn
plz solve plz plz quickly as possible as
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Answered by
5
sn = n/2(2a+(n-1))d
sn =10/2(2×20+(10-1))40
sn=5(40+360)
sn=5×400
sn=2000
mohmmedsufiyanali19:
thanks
Answered by
4
Sn = n/2{2a+(n-1)d}
= 10/2{2×20+(10-1)40
= 5{40+9×40}
=5(40+360)
=5×400
=2000
= 10/2{2×20+(10-1)40
= 5{40+9×40}
=5(40+360)
=5×400
=2000
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