Question

IN AN AP ,if a =5 d=3 find t10

Answer 1

Let a be the first term and d be the common difference.

Given that a=5, d = 3.

We know that sum of n terms of an AP tn = a + (n - 1) * d

                                                                  t10 = 5 + (10 - 1) * 3

                                                                        = 5 + 30 - 3

                                                                        = 5 + 27

                                                                        = 32.


Hope this helps!

Answer 2

Answer:

Given:-

The First term of an ap (a1) = 5

the common difference (d) = 3

To Find:-

The 10th term of the Ap

Solution:-

a1 = 5

d = 3

So we know to find out any term of an ap we use an = a + ( n -1 ) d

where,

• a = 1st term
• n = number of terms
• d = common difference

To find 10th term

↦a10 = a + ( n-1 )d

↦a10 = 5 + ( 10 - 1)3

↦a10 = 5 + 9 × 3

↦a10 = 5 + 27

↦a10 = 32

Therefore , the 10th term of the ap is 32.