Question

In an ap if an=2n+1 then the common difference of given progression is

Answer 1

Answer:

2

Step-by-step explanation:

Given that, $a_{n} = 2n + 1$

Then, $a_{1} = 2(1) + 1 = 2 + 1 = 3$

and $a_{2} = 2(2) + 1 = 4 + 1 = 5$

Thus, common difference, $d = a_{2} - a_{1} = 5 - 3 = 2$

Alternatively, you could have written:

$a_{n - 1} = 2(n - 1) + 1 = 2n - 2 + 1 = 2n -1$

Thus, common difference, $d = a_{n} - a_{n - 1} = (2n + 1) - (2n - 1) = 1 + 1 = 2.$

Answer 2

Now, we are given an arithmetic progression whose nth term is given as (2n+1). ... So, the second term is given as a2=(2×2)+1=5. Now, the common difference d=a2−a1=5−3=2.