in an AP if S25 = 1275 and S24 = 1176 then a25 = a)99 b)98 c)97 d)96
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Answer:
a)99
Step-by-step explanation:
first- S²⁵=25a+300d
S²⁴= 24a+276d
now,. 25a +300d=1275-------(1). ×24
24a + 276d = 1176-------(2)×25
by using elimination method
We have, 600a+7200d=30600
-(600a+6900d=29400)
=300d=1200
d=4
by putting value of d in (1)
we have a= 3
thus, a 25 = a+ 24 d
= 3 +24× 4
=3+96
= 99
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