Question

Slope of line 3x+4y+2=0 is:
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Answer 1

Answer:

Let us use trial and error method and find any 2 satisfying points.

$A (0,-0.5)$

$B (-2 ,1)$

Now,

$x_1=0\\x_2=-2\\y_1=-0.5\\y_2=1$

$Slope=\frac{y_2-y_1}{x_2-x_1}$

        $=\frac{1+0.5}{-2-0}$

       $=\frac{1.5}{-2}$

       $=-0.75$

Alternate method:

We are given that  $3x+4y+2=0$.

$y=\frac{-3x-2}{4}$

$y=\frac{-3}{4} x-\frac{1}{2}$

$y=mx+c$

$m=-\frac{3}{4} =-0.75$