Question

In an ap if Sn=4n-n²then a2=​

Answer 1

Answer:

Sn = 4n²- n²

S1 = 4(1)² - 1

S1 = 4 - 1

S1 = 3

S2 = 4(2) - 2²

S2 = 8 - 4

S2 = 4

a2 = S2 - S1

a2 = 4 - 3

a2 = 1

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Answer 2

Given :-

In an AP

    ↪    Sₙ = 4 n - n²

To find :-

    ↪   the second term of AP = a₂

Solution :-

sum of first term of AP will give us first term

hence,

⇨    a₁ = S₁ = 4 (1) - (1)² = 4 - 1

⇨    a₁ = 3

sum of first two terms = a₁  +  a₂  

hence,

⇨   a₁ + a₂ = S₂ = 4(2) - (2)² = 8 - 4

⇨   a₁ + a₂ = 4

putting value of a₁

⇨   3 + a₂  = 4

⇢   a₂ = 1

Hence,

value of a₂ will be 1

i.e, second term of AP will be 1 .