Question

in an ap ,if the 12th term is-13 and i5s fourth terms is 24 find the sum of its frist ten terms​

Answer 1

A12 = -13

A4 = 24

An = a+(n-1)d

•°• A12 = a+(12-1)d

=> -13 = a+11d ----------(1)

•°• A4 = a+(4-1)d

=>24 = a+3d-------------(2)

subtracting eqn(1) from (2):-

=>37= -8d

=>d= -37/8

putting d in eqn(1):-

-13=a+11(-37/8)

find out a from here ..

and ,

put it on formula ;

Sn=n/2{2a+(n-1)d}

to get the answer ☺️✌️✌️

Answer 2

Answer:

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Step-by-step explanation: