Question

In an AP if the first term is 38 and 68th term is 73 then find its 31 st term

Answer 1

Answer:

The $31^{th}$ term of the AP is 3596/67 or 53.67

Step-by-step explanation:

Given a= 38

68th term is 73

To find n term value T=a+(n-1)d

where T= n term value

           a= first term

            n= sequence number of the term

            d= common difference between term

now, 73= 38+(68-1)d

        35=67d

     d= 35/67

so 31th term

$T_{31th}$ = 38+(31-1)35/67

        = 38+30x35/67

       = 3596/67