in an ap m times of m th term is equal to n times of n th term. Then prove that (m+n) th term zero?
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Hey buddy here is ur answer !!
In Ap
mth = nth is given
To prove that (m+n)th = 0
¤ Here By general formula
nth term of AP is a + (n-1) d
m { a+ (m-1) d } = n { a + (n-1) d }
am + m^2d -md = an + n^2d - nd
a ( m - n ) + ( m + n ) d - ( m - n ) d = 0
(m - n ) { a + (m + n - 1) d } = 0
Hence , we know that
m = n
LHS eq denotes (m+n)th term of AP is 0
Hence proved .
》》 BE BRAINLY 《《
In Ap
mth = nth is given
To prove that (m+n)th = 0
¤ Here By general formula
nth term of AP is a + (n-1) d
m { a+ (m-1) d } = n { a + (n-1) d }
am + m^2d -md = an + n^2d - nd
a ( m - n ) + ( m + n ) d - ( m - n ) d = 0
(m - n ) { a + (m + n - 1) d } = 0
Hence , we know that
m = n
LHS eq denotes (m+n)th term of AP is 0
Hence proved .
》》 BE BRAINLY 《《
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