Question

in an AP s10=150 s9=126 t10=

Answer 1

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HERE IS YOUR ANSWER—

S10 = 150

n/2 [ 2a + ( n-1)d = 150

10/2 [2a + 9d] = 150

5(2a+9d) = 150

10a + 45d = 150

2a + 9d = 30 ———-(1)

Now,

S9 = 126

9/2 [2a + 8d] = 126

9(a + 4d) = 126

a+4d = 14 ———-(2)

Multiplying equation (2) by 2

We get,

2a + 8d = 28 ———-(3)

Subtracting equation (1) and (3)

2a + 9d = 30

-2a - 8d = -28

=> d = 2

So, a = 6

Now, t 10 = a + (n-1) d

=> 6 + (10-1)2

=> 6 + (9)2

=> 6 + 18

=> 24

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