In an AP,S5+S7=167...n S10=235.
Then find the AP??
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S5+S7=5/2 (2a+4d)+7/2 (2a+6d)
where a is the first term and d is the common ratio
=S5+S7=5a+10d+7a+21d=167
similarly S10=10a+45d=235
on solving the two equations simultaneously we get a=1 and d=5
where a is the first term and d is the common ratio
=S5+S7=5a+10d+7a+21d=167
similarly S10=10a+45d=235
on solving the two equations simultaneously we get a=1 and d=5
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