in an AP ten times the 10th term equals fifteen times the 15th term. prove that the 25th term of the AP is 0
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Let the first term be a.
Let the second term be d.
We know n th term is a+(n-1)d
So:
10th term=15th term
10[a+(10-1)d]=15[a+(15-1)d]
=10[a+9d]=15[a+14d]
=10a+90d=15a+210d
=10a-15a=210d-90d
=-5a=120d
=a=120/-5*d
=a=-24d
=a+24d=0
=a+(25-1)d=0
So 25 th term is zero since it is a+(25-1)d
Hope it helps you.
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