In an ap the 12 term is -13 and sum of first 4term is 24 find the first 3term of ap
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a12=-13
a+11d=-13
2a+22d=-26 (1)
S4=24
2 (2a+3d)=24
2a+3d=12 (2)
subtracting eq 2 from eq 1
19d=-38
d=-2
2a-6=12
a=9
first 3 terms are 9,7,5
a+11d=-13
2a+22d=-26 (1)
S4=24
2 (2a+3d)=24
2a+3d=12 (2)
subtracting eq 2 from eq 1
19d=-38
d=-2
2a-6=12
a=9
first 3 terms are 9,7,5
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