Question

in an ap the first term is 8 nth terms is 33 and the sum of its first n terms is 123 find n and d​

Answer 1

Given,

a=8,a

n

=33,S

n

=123

a

n

=a+(n−1)d

⇒33=8+(n−1)d

⇒(n−1)d=25

S

n

=

2

n

[2a+(n−1)d]

123=

2

n

[2×8+25]

246=n[16+25]

⇒n=

41

246

∴n=6

(n−1)d=25

(6−1)d=25

∴d=5

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