In an AP,the fourth term is 10 times the first term .Then show that it's 6th term is 4 times the second term
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Step-by-step explanation:
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Step-by-step explanation:
a+3d=10a
3d=10a-a
d=9a/3
d=3a
a+5d
a+5(3a)
=a+15a
=16a
16a=4(a+d)
16a=4a+4d
16a=4a+4(3a)
16a=4a+12a
16a=16a
Both are equal
Hence proved
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