In an AP the sum of first
11 terms is 14 & the Sum of
- next 11 terms is 55.
Find the first of term of AP
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Step-by-step explanation:
Let the AP be a, a+d, a+2d, ...; ==> First term is a and common difference is d
ii) Sum of first 11 terms is: (11/2)*(2a + 10d) = 44
This simplifies to: a + 5d = 4 ------ (1)
iii) Sum of next 11 terms = 55; so sum of first 22 terms is 44 + 55 = 99.
==> (22/2)(2a + 21d) = 99
==> 2a + 21d = 9 ------- (2)
iv) Solving (1) & (2), we have a = 39/11 and d = 1/11
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