in an ap the sum of first 11 terms is 44 and that of the next 11 terms is 55 find the ap
who is answering this question can please send in photo format please
Answers
Answered by
1
Answer:Let the AP be a, a+d, a+2d, ...; ==> First term is a and common difference is d
ii) Sum of first 11 terms is: (11/2)*(2a + 10d) = 44
This simplifies to: a + 5d = 4 - (1)
iii) Sum of next 11 terms = 55; so sum of first 22 terms is 44 + 55 = 99.
==> (22/2)(2a + 21d) = 99
==> 2a + 21d = 9 - (2)
iv) Solving (1) & (2), we have a = 39/11 and d = 1/11
Hence, AP is; 39/11, 40/11, 41/11, 42/11, .
Step-by-step explanation:
Attachments:
Similar questions