in an AP the sum of first 5th term is 55 and fourth term is 5 more than the sum of next two term find AP
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Let 5terms of AP be a-2d, a-d, a, a+d,a+2d.
Sum of 5terms =55
a-2d+a+2d+a-d+a+d+a=55
5a=55
a=11
According to question
a+d=a+2d+a+3d+5
a+4d=-5
11+4d=-5
4d=-16
d=-4
Ap is 19,15,11,7,3
Verify a4=7
3-1+5=7=a5+a+6+5
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