Question

in an ap, the sum of its first ten terms is 150 and the sum of its next term is 550. Find the ap​

Answer 1

Answer:

n = 10, Sn = - 550 Here a = a + 10d - 550 = (10/2)[2(a + 10d) + (10-1)d] - 550 = 5[2a + 29d] Dividing through by 10, -110 = 2a + 29d ----------(2) Solving (1) and (2) we get d = -4 and a = 3.

Step-by-step explanation:

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Answer 2

Answer:

the common difference of the given AP . S₁₀ = -150. ⇒ S₁₀ = 10/2 [ 2a + ( 10 - 1 ) d ]. Clearly, the sum 20 term = - 150 + (-550)..

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