In an AP the sum of the first ten terms is -80 and the sim of its next ten terms is -280 . Find the AP ?
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2a+9d=-16
2a+29d=-56
20d=-40
d=-2
a=1
2a+29d=-56
20d=-40
d=-2
a=1
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Step-by-step explanation:
let the first term and d is the common differences of AP
= Sn=n/2{2a+(n-1)d}
now.............
=S10=10/2{2a+(10-1)d}
= -80=5(2a+9d)
= 2a+9d=-16.........(1)
again....
S20-S10=-280
=20/2{2a+19d}+80=-280
= 10{2a+19d}=-360
= 2a+19d=-36.........(2)
solve this two equation
then..
we found
d=-2
a=1
so...
AP=1,-1,-3,-5......
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