in an ap tn = 99 a= 7 and d= 2 find the value of n
Fortunegiant:
tn or an or sn ??
sn is sum of n terms in the series
Answers
Answered by
8
we know that in an AP the general term is given by a+(n-1)d
according to question a=7;d=2 and last term is 99
putting all these values
99=7+(n-1)2
99-7=(n-1)2
92/2=n-1
46=n-1
n=47
hence,required value of n is 47
Answered by
3
given tn=99
a+(n-1)d=99
substitute a=7, d=2
7+(n-1)2=99
(n-1)2=99-7
(n-1)2=92
(n-1)=92/2
n-1=46
n=46+1
n=47
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