Question

In an approximate model of the human heart action, speed of 22gm of blood increases from

30cm/s to 40cm/s during a time 0.08s, the force exerted by the heart in dyne is​

Answer 1

The force exerted by the heart is 2750 Dyne

Explanation:

Initial Velocity, u=30cm/s

Final Velocity,  v=40cm/s

mass,m = 22 g

time, t=0.08s

Acceleration,a = (v-u)/t

(40-30)/0.08 = 125 m/s^2

So force exerted = m*a

22*125

=2750 dyne

Answer 2

Given that,

Mass of blood, m = 22 gm

Initial speed, u = 30 cm/s

Final speed, v = 40 cm/s

Time, t = 0.08 s

To find,

The force exerted by the heart.

Solution,

The force exerted by the heart is given by the product of mass and its acceleration. Acceleration is equal to the change in velocity per unit time. So,

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{22\ g\times (40-30)\ cm/s}{0.08\ s}\\\\F=2750\ g-cm/s^2$

In CGS unit, force is given by Dyne. So, the force exerted by the heart is 2750 Dyne.

Learn more,

Force

https://brainly.in/question/11566247