Question

In an aquarium the number of gold fish is less than the number of Silver fish by 25% by what percent is the silver fish more than the gold fish ?​

Answer 1

Step-by-step explanation:

75 percent is the right answer

Answer 2

Working out:

Let's do it by two methods:

METHOD-1)

Given in the question, The number of goldfish is less than the silverfish by 25%.

Let,

Number of silverfish be x

Then number of goldfish = x - 25% of x

$\sf{ \longrightarrow{x - \dfrac{25}{100} \times x}}$

$\sf{ \longrightarrow{x - 0.25x}}$

$\sf{ \longrightarrow{0.75x}}$

We have to find by how much % is the silver fish more than the goldfish. So, here we are comparing as comparison to the goldfish.

How much more?

$\sf{ \longrightarrow{x - 0.75x}}$

$\sf{ \longrightarrow{0.25x}}$

Now by how much more in terms of %?

$\sf{ \longrightarrow{\dfrac{0.25x}{0.75x} \times 100}}$

$\sf{ \longrightarrow{ \dfrac{100}{3} \%}}$

${ \longrightarrow{ \boxed{ \sf{33.33\%}}}}$

METHOD-2)

Let the number of silverfish be 100

Then number of goldfish will be 100 - 25% of 100

That is equals to 75

% by which the silverfish is more:

$\sf{ \longrightarrow{ \dfrac{100 - 75}{75} \times 100}}$

$\sf{ \longrightarrow{ \dfrac{25}{75} \times 100}}$

$\sf{ \longrightarrow{ \dfrac{100}{3} \%}}$

$\sf{ \longrightarrow{ \boxed{33.33\%}}}$

And we are done !!