in an aqueous solution mole fraction of water is 0.75.the molality of the solution is
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Answer:it is 18.5
Explanation:so the mole fraction of solvent is given 0.75
1-0.75=0.25 ( mole frac. of solute)
Now making 2 equations
0.25=nA/nA+nB.......1
0.75=nB/nB+nA........2 { let 1÷2}
:1/3=nA/nB
For molality.. No. of moles of solute/mass of solvent in kg
So no. of moles of solvent = given mass of solvent/mass of solvent
3×18= given mass of solvent
By putting in formula
1/3×18/1000
1000/54
18.5m
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