Question

In an arbitrary scale of temperature water freezes at 40°C and boils at 290°C find the boiling point of a liquid in this scale if it's boiling point in the standard scale is 62°C

Answer 1

C/100=(X-LFP)/(UFP-LFP)
where C= temp in Celsius scale
UFP = upper fixed point
LFP= lower fixed point
62/100=(X-40)/(290-40)
62/100=(X-40)/250
0.62×250=X-40
155=X-40
X=155+40
X=195

Answer 2

Concept: Arbitrary Scale pictured as man of affairs. Units or a.u. In measurements whereby absolute values will can't be obtained, one will oft use the term man of affairs. Units or a.u. The boiling purpose of water is that the temperature at that the liquid vapor pressure is adequate to the pressure encompassing the body, and also the body transforms into a vapor.

Given: Water freezes at 40°C and Boils at 290°C.

Find: Calculate the boiling point of the liquid.

Solution: UFP= Upper Fixed Point

LFP= Lower Fixed Point

C/100= X-LFP/ UFP-LFP

62/100= X-40/ 290-40

62/100= X-40/250

0.62×250=X-40

155=X-40

X= 155+40

X= 195°C

Final answer: Boiling point of the liquid is 195°C

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