Question

In an arithmetic progression, a = 2, d = 3 and l = 14. Find the probability to select a number in
above A.P., is multiple of 3.

Answer 1

Hi ,

It is given that ,

In an A.P

a = 2 , d = 3 , l = 14

Let number terms in A.P = n

We know that ,

a + ( n - 1 )d = l

2 + ( n - 1 )3 = 14

( n - 1 )3 = 14 - 2

n - 1 = 12/3

n - 1 = 4

n = 4 + 1

n = 5

Therefore ,

2 , 5 , 8 ,11 ,14 are 5 terms of A.P

Let E is an event which is multiple

3 in given A.P

Total possible outcomes={ 2,5,8,11,14}

Number of total possible outcomes

= 5 ---( 1 )

Number of favourable outcomes = 0

( multiple of 3 )---( 2 )

P( E ) = ( 2 ) / ( 1 )

= 0/5

= 0

I hope this helps you.

:)