In an arithmetic sequence the sum of first and tenth terms is 25. Find the sum of the fifth and sixth terms
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Answer:
Step-by-step explanation:
a1 = 25
a10 = 25
d = 0
S5 = n/2 * {(2a)+(n-1)*d}
S5 = 5/2 {(2*25)+(5-1)*0}
= 5/2 {50+0}
= 5/2 * 50
= 5 * 25
s5 = 125
s6 = s5 + a
= 125 + 25
= 150
Answered by
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Answer:
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