Question

in an Arthematic progression 9th term is 9 times is equal to 13th term is 13 times,then show that 22nd term is zero

Answer 1

let a is the first term and d is the common difference of AP

now,

9 × 9th term = 13 × 13th term

9{ a + (9 -1)d} = 13 { a + (13 -1 )d }

9a + 72d = 13a + 156d

4a + 84d = 0

a + 21d = 0

now,

T22 = a + (22 -1)d = a +21d =0

Answer 2

Answer:

Step-by-step explanation:

This is the answer