Question

in an arthematic progression third and nineth terms sum is 8 what is the value when first 11 terms are added

Answer 1

Answer:

The third term t

3

=a+3d

The ninth term t

9

=a+8d

t

3

+t

9

=2a+10d=8

Sum of first 11 terms of an AP is given by

S

11

=

2

11

[2a+10d]

S

11

=

2

11

×8=44

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