Question

Number of molecule s present in 8 g of oxygen gas is __________ *
1 point
(a) 6.022 x 10²³
(b) 3.011 x 10²³
(c) 12.044 x 10²³
(d) 1.505 x 10²³​

Answer 1

Answer:

1 g contains → 6.022 × 1023 / 32 molecules of di oxygen. ⇒ 1 g contains → 0.188 × 1023 molecules of di oxygen. ∴ 8 g contains → 0.188 × 8 × 1023 molecules of di oxygen. =1.505 * 1023 molecules.

so ur answer is (d) 1.505 x 10²³

Answer 2

Answer:

Opt c

Explanation:

1 mol gas contains 6.022×10^23 molecules.

And mass of 1 mol= molar mass