Question

In an atom, which has 2K, 8L, 18M and 2N electrons in the ground state. The total number of electrons having magnetic quantum number , m = 0 is

Answer 1

Answer is 14

2K 8L 18M 2N

Here means..

=> 2K = 1s2

=> 8L = 2s2 + 2p6

=> 8M = 3s2 + 3p6 +3d10

=> 2N = 4s2

For s, m =0 is 1

And For p, m= 0 is 1..

Also, for d, m =0 is 1

So.. Totally.. Each s,p has m= 0 and 2 electrons with spins +½ and - ½

2K has = 2 electron at m=0

8L has = 4 electrons at m=0 ;

(since, S and P both are present)

18M has = 6 electrons at m =0 ;

(since, s, p, and d are present)

2N has = 2 electrons at m=0 ;

So total number of electrons at

m= 0 is (2+4+6+2)=14

Answer 2

Answer:

the answer for this is 14