Question

In an atom which has 2K ,8L,8M,2N Electrons in the ground state , the total number of electrons having l=1 are

Answer 1

8 totall no. Of electrons

Answer 2

The number of electron is 12

Explanation:

We are given that the atom in ground state has 2K, 8L, 8M, and 2N electrons.

So as per the electronic configuration, we have:

$2 K=1 s^{2}$

$8 L=2 s^{2}+2 p^{6}$

$8 M=3 s^{2}+3 p^{6}+3 d^{0}$

$2 N=4 s^{2}$

If l = 0, it means sub-shell s wherein the magnetic quantum=0

For l = 1, sub-shell is p, wherein the magnetic quantum can be -1, 0, 1

So, for s sub- shell, we have 4 orbitals and p sub-shell, we have 2 orbitals.

The total number of orbitals= 6, total number of shells in which we need to calculate the electrons is 2(s and p).

So number of electrons = (2 $\times$ Number of orbitals)

$= 2 \times 6$

Number of electron = 12